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Electric Charges And Fields

Question

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A charged particle is suspended equillibrium in a uniform vertical electric field of intensity 2000V/m. If mass of the particle is 9.6×10^-16 kg, the charge on it and excess number of electrons on the particle respectively are (g=10m/s²)

4.8×10^-19 C,3

5.8×10^-19 C,4

3.8×10^-19C, 2

2.8×10^-19C, 1

Solution

4.8×10^-19 C,3

Charge of the particle is given by

$q E = mg or q = \frac{mg}{E} = \frac{9.6 \times 10^{- 16} \times 10}{20000} = 4.8 \times 10^{- 19} When there is an excess of n electrons on the particle, then q = ne so, n = \frac{q}{e} = \frac{4.8 \times 10^{- 19}}{1.6 \times 10^{- 19}} = 3$

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Electric Charges And Fields

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Electric Charges And Fields

A charged particle is suspended equillibrium in a uniform vertical electric field of intensity 2000V/m. If mass of the particle is 9.6×10-16 kg, the charge on it and excess number of electrons on the particle respectively are (g=10m/s2) 4.8×10-19 C,3 5.8×10-19 C,4 3.8×10-19C, 2 2.8×10-19 C, 1

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