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Electromagnetic Induction

Question

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The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance

0.138 H

138.88 H

13.89

1.389 H

Solution

13.89

Energy stored in the inductor,
U = 25 x 10^-3 J

Current, I = 60 mA
Energy stored in inductor $U = \frac{1}{2} L I^{2} 25 x 10^{- 3} = \frac{1}{2} x L x (60 x 10^{- 3})^{2} L = \frac{25 x 2 x 10^{6} x 10^{- 3}}{3600} = 13.89 H$

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Electromagnetic Induction

The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance

0.138 H

138.88 H

13.89

1.389 H

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When power is drawn from the secondary coil of the transformer, the dynamic resistance

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For Daily Free Study Material Join wiredfaculty

Electromagnetic Induction

The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance 0.138 H 138.88 H 13.89 1.389 H

Some More Questions From Electromagnetic Induction Chapter

When power is drawn from the secondary coil of the transformer, the dynamic resistance

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance

0.138 H

138.88 H

13.89

1.389 H