Question
A parallel plate air capacitor is charged to a potential difference of V volts. After disconnecting thecharging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates
-
decreases
-
does not change
-
becomes zero
-
increases
Solution
D.
increases
Charge remains constant after charging.
If the battery is removed after charging then the charge stored in the capacitor remains constant.
q = constant
Change in capacitance
As 
Hence, 
Hence, potential difference between the plates
or 
As capacitance decreases, so potential difference increases.
