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Wave Optics

Question

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The half-life of a radioactive substance is 3.6 days. How much of 20 mg of this radioactive substance will remain after 36 days?

0.0019 mg

1.019 mg

1.109 mg

0.019 mg

Solution

0.019 mg

Half time T_1/2 = 3.6 days

Initial quantity N₀ =20 mg

Total time = 36 days

The number of half lives

$n = \frac{t}{T_{1 / 2}} = \frac{36}{3.6} = 10 Hence the mass of radioactive substance left after 10 half lives N = N_{o} \times {(\frac{1}{2})}^{n} = 20 \times \frac{1}{1024} N = 0.0019 mg$

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Wave Optics

The half-life of a radioactive substance is 3.6 days. How much of 20 mg of this radioactive substance will remain after 36 days?

0.0019 mg

1.019 mg

1.109 mg

0.019 mg

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For Daily Free Study Material Join wiredfaculty

Wave Optics

The half-life of a radioactive substance is 3.6 days. How much of 20 mg of this radioactive substance will remain after 36 days? 0.0019 mg 1.019 mg 1.109 mg 0.019 mg

Some More Questions From Wave Optics Chapter

In junction diode, the holes are because of

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The half-life of a radioactive substance is 3.6 days. How much of 20 mg of this radioactive substance will remain after 36 days?

0.0019 mg

1.019 mg

1.109 mg

0.019 mg