The distance between the poles of horse shoe magnet is 10 cm and its pole strength is 10⁴ A. The magnetic field induction at point P mid-way between the poles is

$8 \times 10^{- 9} tesla$

4×10^-19tesla

2×10^-9 tesla

zero

Solution

$8 \times 10^{- 9} tesla$

$B = B_{1} + B_{2} = \frac{μ_{0}}{4 π} (\frac{m_{1}}{r_{1}^{2}} + \frac{m_{2}}{r_{2}^{2}}) as m_{1} = m_{2} and r_{1} = r_{2} so, B = \frac{μ_{0}}{4 π} \frac{2 m_{1}}{r_{1}^{2}} = 10^{- 7} \frac{2 \times 10^{- 4}}{{(5 \times 10^{- 2})}^{2}} B = 8 \times 10^{- 9} T$

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Electric Charges And Fields

The distance between the poles of horse shoe magnet is 10 cm and its pole strength is 10⁴ A. The magnetic field induction at point P mid-way between the poles is

$8 \times 10^{- 9} tesla$

4×10^-19tesla

2×10^-9 tesla

zero

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Electric Charges And Fields

The distance between the poles of horse shoe magnet is 10 cm and its pole strength is 104 A. The magnetic field induction at point P mid-way between the poles is 8×10-9 tesla 4×10-19 tesla 2×10-9 tesla zero

Some More Questions From Electric Charges and Fields Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The distance between the poles of horse shoe magnet is 10 cm and its pole strength is 10⁴ A. The magnetic field induction at point P mid-way between the poles is

$8 \times 10^{- 9} tesla$

4×10^-19tesla

2×10^-9 tesla

zero