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Wave Optics

Question

The radius of electron second stationary orbit in Bohr's atom is R. The radius of third orbit will be

2.25R

3R

R/3

9R

Solution

$r_{n} = (\frac{n^{2}}{m}) {(\frac{h}{2 π})}^{2} \frac{4 {πε}_{o}}{e^{2}} r_{n} \propto n^{2} For second orbit n = 2 r_{2} = R for third orbit n = 3 r_{3} = {(3)}^{2} R r_{3} = 9 R$

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Wave Optics

The radius of electron second stationary orbit in Bohr's atom is R. The radius of third orbit will be

2.25R

3R

R/3

9R

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For Daily Free Study Material Join wiredfaculty

Wave Optics

The radius of electron second stationary orbit in Bohr's atom is R. The radius of third orbit will be 2.25R 3R R/3 9R

Some More Questions From Wave Optics Chapter

In junction diode, the holes are because of

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The radius of electron second stationary orbit in Bohr's atom is R. The radius of third orbit will be

2.25R

3R

R/3

9R