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Wave Optics

Question

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The enregy of a photon corresponding to the visible light maximum wavelength is nearly

7ev

3.2eV

1eV

1.6eV

Solution

D.

1.6eV

In the visible light λ_max= 7800A^o

$E = \frac{hc}{λ} = \frac{12375}{7800} eV = 1.6 eV$

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