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Electric Charges And Fields

Question

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An AC supply gives 30V_rms which is fed on a pure resistance of 10 ohm. the power dissipated in this is

90watt

45watt

90.2watt

180watt

Solution

A.

90watt

$P = \frac{V^{2}}{R} = \frac{{(30)}^{2}}{10} = 90 watt$

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