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Electric Charges And Fields

Question

Two small magnets each of magnetic moment 10 Am² are placed in end on position 0.1 m apart from their centres. The force acting between them is

0.6N

0.06N

0.06×10⁷N

0.6×10⁷N

Solution

0.6N

$F = \frac{μ_{o}}{4 π} \frac{6 M_{1} M_{2}}{r^{4}} = 10^{- 7} \times \frac{6 \times 10 \times 10}{{(0.1)}^{4}} = 0.6 N$