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Electric Charges And Fields

Question

In a neon discharge tube 2.9 x 10 Ne¹⁸ ions move to be the right per second while 1.2 x 10⁸ electron move to the left per second electric charge is 1.6 x 10^-19C. The current in discharge tube is

0.66A towards left

0.66 A towards left

1A towards right

Zero

Solution

0.66 A towards left

Current due to both types of ions are in the same direction towards the right so

i=i₁+i₂

$i = 2.9 \times 10^{18} \times 1.6 \times 10^{- 19} + 1.2 \times 10^{18} \times 1.6 \times 10^{- 19} i = 0.66 A$