A positively charged ball hangs from a silk thread. we put a positive test charge qo at a point and measure F/qo, then it can be predicted that the electric field strength E
>F/qo
=F/q
<F/qo
Cannot be estimated
A.
>F/qo
Due to the presence of test charge qo in front of the positively charged ball, there would be a redistribution of charge on the ball. In the redistribution of charge, there will be less charge on the front half surface and more charge on the back half surface. As a result, the net force F between ball and charge will decrease, i.e., the electric field is decreased. Thus, the actual electric field will be greater than F/qo