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Dual Nature Of Radiation And Matter

Question
CBSEENPH12040159

An isotropic point source of light is suspended h metre vertically above the centre of the circular table of radius r metre. Then, the ratio of illumenances at the centre to that at the edge of the table is

  • 1 + r2h2

  • 1 + h2r2

  • 1 + r2h23/2

  • 1 + h2r23/2

Solution

C.

1 + r2h23/2

According to the question, the situation is shown in the figure below,

E1 = I(LO)2 = Ih2 ... (i)

The illumination at the edge A is given by

E2 = I cos θ(LA)2 = I cos θ(h2 + r2) .... (ii)From figure, cos θ = h(h2 + r2) E2 = Ih(h2 + r2)3/2Dividing eq (i) by eq (ii), we getE1E2 = I/h2Ih/(h2+r2)3/2 = (h2+ r2)3/2h3 = (h2+ r2)3/2h2 = 1 + r2h23/2