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Nuclei

Question
CBSEENPH12040151

Radioactive decay will occur as follows

Rn86220      PO84216 + He24 Half life = 55sPO84216      Pb82212  + He24 Half life = 0.66 sPb82812    BL82212 + λ°e Half life = 10.6 h

If a certain mass of radon (Rn = 220) is allowed to decay in a certain container; then after 5 minutes the element with the greater mass will be

  • radon

  • polonium

  • lead

  • bismuth

Solution

C.

lead

Let Mo be initial mass of Rn -220

Number of half-lives of Rn in 5 minutes = 5min/55s

 = 5 x 6055  5.5 Mass of Rn - 220 (left) = 125.5 Mo =M05

Therefore, the mass converted into Po - 216 is (44/45)

Mo, number of half-lives of Po- 216 in 5 minutes

 = 5 min0.66 = 3000.66  455 Mass of Po - 216 left = 12455  x 4445 M0    0

This means that Po - 216 formed will soon decay to lead. Hence, the lead will have maximum mass nearly (44/45)M0