N lamps each of resistance r, are fed by the machine of resistance R. If light emitted by any lamp is proportional to the square of the heat produced, prove that the most efficient way of arranging them is to place them in parallel arcs, each containing n lamps, where n is the integer nearest to.
(NRr)3/2
(NRr)1/2
B.
As each is containing n lamps, hence,
The resistance of each arc = nr
Number of arcs = N/n
Total resistance S is given by
If E is the emf of the machine, current entering the arcs is E/(R+S) and in each arc is nE/(R+S)N.
Hence, the current passing through each lamp.
Now heat produced per second in the lamps is
H = NI2
since, light emitted is proportional to H2 therefore, the light produced is maximum when H2 and hence H is maximum or is minimum. Hence, we can write,
This is minimum when or very small or n is closely equal to (NR/r)1/2