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Nuclei

Question
CBSEENPH12040150

N lamps each of resistance r, are fed by the machine of resistance R. If light emitted by any lamp is proportional to the square of the heat produced, prove that the most efficient way of arranging them is to place them in parallel arcs, each containing n lamps, where n is the integer nearest to.

  • rNR3/2

  • NRr1/2

  • (NRr)3/2

  • (NRr)1/2

Solution

B.

NRr1/2

As each is containing n lamps, hence,

The resistance of each arc = nr

Number of arcs = N/n

Total  resistance S is given by

1S = Σ1nr = Nn1nrS = n2rN Total resistance = R + S  + (n2r)N

If E is the emf of the machine, current entering the arcs is E/(R+S) and in each arc is nE/(R+S)N.

Hence, the current passing through each lamp.

I = nEN(R +n2r/N) = ENRn + nrN-1

Now heat produced per second in the lamps is 

H = NI2

since, light emitted is proportional to H2 therefore, the light produced is maximum when H2 and hence H is maximum or Rn + nrN is minimum. Hence, we can write,

Rn + nrN = Rn1/2 - nrN1/2 + 2RrN1/2

This is minimum when R/n - nr/N = 0 or very small or n is closely equal to (NR/r)1/2