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Semiconductor Electronics: Materials, Devices And Simple Circuits

Question
CBSEENPH12040145

In the circuit shown in the figure, the input voltage Vi is 20 V, VBE = 0 and VCE = 0. The values of IB, IC and β are given by

  • IB = 40 μA, IC = 10 mA, β = 250

  • IB = 25 μA, IC = 5 mA, β = 200

  • IB = 40 μA, IC = 5 mA, β = 125

  • IB = 20 μA, IC = 5 mA, β = 250

Solution

C.

IB = 40 μA, IC = 5 mA, β = 125

VBE = 0,

Vi  = 20 V

VCE = 0

Vb = 0 (earthed)

Ic(20-0)4 x 103 = 5 x 103 = 5 mA

Or

Vi = 0 + IBRB

 20  = IB x 500 x 103 IB = 2500 x 103 = 40μAβ = ICIb = 25 x 10-340 x 10-6 =125