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Atoms

Question

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The ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom, is

1:1

1:-1

1:-2

2:-1

Solution

B.

1:-1

In a Bohr orbit of the hydrogen atom Kinetic energy,

$k = \frac{k z e^{2}}{2 r_{n}} T o t a l e n e r g y, E = \frac{- k z e^{2}}{2 r_{n}}$

so, Kinetic energy: total energy = 1:-1

Some More Questions From Atoms Chapter

Draw graphs showing a variation of the photoelectric current with applied voltage for two incident radiations of equal frequency and different intensities. Mark the graph for the radiation of higher intensity.

Four nuclei of an element undergo fusion to form a heavier nucleus, with the release of energy. Which of the two — the parent or the daughter nucleus — would have higher binding energy per nucleon?

Which of the following transitions in hydrogen atoms emit photons of highest frequency?

The energy spectrum of β-particles [number N(E) as a function of β-energy E] emitted from a radioactive source is

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