A galvanometer having a coil resistance of 60 Ω shows full-scale deflection when a current of 1.0 A passes through it. It can be converted into an ammeter to read currents up to 5.0 A by

putting in parallel a resistance of 240 Ω

putting in series a resistance of 15 Ω

putting in series a resistance of 240 Ω

putting in parallel a resistance of 15 Ω

Solution

putting in parallel a resistance of 15 Ω

To convert a galvanometer to ammeter a small resistance is connected in parallel to the coil of the galvanometer.
Here G₁ = 60 Ω, Ig = 1.0 A, I = 5 A
I_g G₁ = (I - I_g) S

$straight S space equals space fraction numerator straight I subscript straight g straight G subscript 1 over denominator straight I space minus straight I subscript straight g end fraction space equals space fraction numerator 1 over denominator 5 minus 1 end fraction space straight x space 60 space equals space 15 space straight capital omega$
Putting 15 Ω resistance in parallel.

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