The two ends f a rod of length L and a uniform cross -sectional area A are kept at two temperatures T₁ and T₂ (T₂ > T₁) .The rate of heat transfer, dQ/dt, through the rod in steady state is given by

$dQ over dt space equals space fraction numerator KL left parenthesis straight T subscript 1 minus straight T subscript 2 right parenthesis over denominator straight A end fraction$
$dQ over dt space equals space fraction numerator straight K space left parenthesis straight T subscript 1 minus straight T subscript 2 right parenthesis over denominator LA end fraction$
$dQ over dt space equals space KLA space left parenthesis straight T subscript 1 minus straight T subscript 2 right parenthesis$
$dQ over dt space equals space fraction numerator KA space left parenthesis straight T subscript 1 minus straight T subscript 2 right parenthesis over denominator straight L end fraction$

Solution

dQ over dt space equals space fraction numerator KA space left parenthesis straight T subscript 1 minus straight T subscript 2 right parenthesis over denominator straight L end fraction

For a rod of length L and area of cross- section A whose faces are maintained at temperature T₁ and T₂ respectively.
Then in steady state, the rate of heat flowing from one face to the other face in time t is given by

$dQ over dt space equals space fraction numerator KA space left parenthesis straight T subscript 1 minus straight T subscript 2 right parenthesis over denominator straight L end fraction$

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