Question
The mean free path of electrons in a metal is 4 x 10-8 m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in unit of V m-1
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8 x 107
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5 x 10-11
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8 x 10-11
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5 x107
Solution
D.
5 x107
Energy = 2eV
eVo = 2eV
⇒ Vo = 2
Now, electric field E = 2 / 4 x 10-8 = 0.5 x 108 = 5 x 107 Vm-1
