Electrostatic Potential And Capacitance

Question

Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be

C/3, V/3

3C, V/3

C/3, 3V

3C ,3V

Solution

C/3, 3V

In series arrangement charge on each plate of each capacitor has the same magnitude. The potential difference is distributed inversely in the ratio of capacitors ie,
V = V₁ +V₂ +V₃ ....
Here, V = 3V
The equivalent capacitance C_s is given by

$1 over straight C subscript straight s space equals space 1 over straight C subscript 1 space plus space 1 over straight C subscript 2 space plus 1 over straight C subscript 3 space plus.. straight C subscript straight s space equals space straight C over 3$

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Electrostatic Potential And Capacitance

Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be

C/3, V/3

3C, V/3

C/3, 3V

3C ,3V

Some More Questions From Electrostatic Potential and Capacitance Chapter

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For Daily Free Study Material Join wiredfaculty

Electrostatic Potential And Capacitance

Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be C/3, V/3 3C, V/3 C/3, 3V 3C ,3V

Some More Questions From Electrostatic Potential and Capacitance Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be

C/3, V/3

3C, V/3

C/3, 3V

3C ,3V