A transistor is operated in common-emitter configuration at V_c = 2 volts such that a change in the base current from 100 μ A to 200 μ A produces a change in the collector current from 5 mA to 10 mA. The current gain is

75

100

150

50

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Solution

For a transistor
I_E = I_B + I_C
where

I_E = emitter current
I_B = base current
I_C = collector current
and current

space beta equals fraction numerator increment straight I subscript straight C over denominator increment straight I subscript straight B end fraction increment straight I subscript straight C space equals space 5 space straight x space 10 to the power of negative 3 end exponent space straight A increment straight I subscript straight B space equals space 100 space straight x space 10 to the power of negative 6 end exponent thin space straight A space beta equals space 5 over 100 space straight x space 1000 space equals space 50 space

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