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Wave Optics

Question
CBSEENPH12040018

A p-n photodiode is fabricated from a semiconductor with a band gap of 2.5 eV. It ca detect a signal of wavelength

  • 6000 Ao

  • 4000 nm

  • 6000 nm

  • 4000 Ao

Solution

D.

4000 Ao

Only signals having wavelength less than threshold wavelength will be detected.
Energy E = hv = hc/λ

λ = hc / E
substituting the values of h, c and E in the above equation

straight lambda space equals space fraction numerator 6.6 space straight x space 10 to the power of negative 34 end exponent space straight x space 3 space straight x space 10 to the power of 8 space over denominator 2.5 space straight x space 1.6 space straight x space 10 to the power of negative 19 end exponent end fraction space equals space 5000 straight A to the power of straight o

As space 4000 space straight A to the power of 0 space less than space 5000 space straight A thin space to the power of straight o
signal space of space wavelength space 4000 space straight A to the power of straight o space can space be space detected space by space the space photodiode.

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