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Wave Optics

Question
CBSEENPH12040017

In the nuclear decay given below,

straight X presubscript straight Z presuperscript straight A space rightwards arrow straight Y presubscript straight Z plus 1 end presubscript presuperscript straight A space rightwards arrow space straight B presubscript straight Z minus 1 end presubscript presuperscript straight A minus 4 end presuperscript asterisk times space rightwards arrow space straight B presubscript straight Z minus 1 end presubscript presuperscript straight A minus 4 end presuperscript
the particle emitted in the sequence are

  • β, α, γ

  • γ, β, α, 

  •  β,γ, α

  • α, β,γ 

Solution

A.

β, α, γ

In a nuclear reaction conservation of charge number and mass, the number must hold good.
Alpha particles are positively charged particles with charge +2e and mass 4 m. Emission of an α particle reduces the mass of the radionuclide by 4 and its atomic number by 2. β- particles are negatively charged particles with rest mass as well as charge same as that of electrons. γ  particles carry no charge and mass.
Radioactive transition will be as follows.
straight X presubscript straight Z presuperscript straight A space rightwards arrow space straight Y presubscript straight Z plus 1 end presubscript presuperscript straight A space plus space straight beta subscript negative 1 end subscript superscript 0

straight Y presubscript straight Z plus 1 end presubscript presuperscript straight A space rightwards arrow space straight beta presubscript straight Z minus 1 end presubscript presuperscript straight A minus 4 end presuperscript space plus straight alpha subscript 2 superscript 4

straight beta presubscript straight Z plus 1 end presubscript presuperscript straight A minus 4 end presuperscript space rightwards arrow space presubscript straight Z minus 1 end presubscript presuperscript straight A minus 4 end presuperscript straight beta space plus space straight gamma subscript 0 superscript 0

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