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Electric Charges And Fields

Question

The thermal emf E in volt of a certain thermocouple is found to vary with temperature difference θ in ^oC between the two junctions according to the relation
$straight E space equals space 30 space straight theta space minus straight theta squared over 15$
The neutral temperature for the thermocouple will be

450^o C

400^o C

225^o C

30^o C

Solution

225^o C

Given,
$straight E space equals space 30 space straight theta space minus straight theta squared over 15 At space neutral space temperature dE over dθ space equals space 0 therefore comma space 30 space minus 20 over 15 space equals space 0 straight theta space equals space 225 to the power of straight o straight C$