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Electric Charges And Fields

Question
CBSEENPH12040006

A condenser of capacity C is charged to a potential difference of V1. The plates to the condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser reduces to V2 is

  • open parentheses fraction numerator straight C left parenthesis straight V subscript 1 minus straight V subscript 2 right parenthesis squared over denominator straight L end fraction close parentheses to the power of 1 divided by 2 end exponent
  • fraction numerator straight C left parenthesis straight V subscript 1 superscript 2 minus straight V subscript 2 superscript 2 right parenthesis over denominator straight L end fraction
  • fraction numerator straight C space left parenthesis straight V subscript 1 superscript 2 space plus straight V subscript 2 superscript 2 right parenthesis over denominator straight L end fraction
  • open parentheses fraction numerator straight C space left parenthesis straight V subscript 1 superscript 2 minus straight V subscript 2 superscript 2 right parenthesis over denominator straight L end fraction close parentheses to the power of 1 divided by 2 end exponent

Solution

D.

open parentheses fraction numerator straight C space left parenthesis straight V subscript 1 superscript 2 minus straight V subscript 2 superscript 2 right parenthesis over denominator straight L end fraction close parentheses to the power of 1 divided by 2 end exponent