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Wave Optics

Question
CBSEENPH12040089

In a radioactive material the activity at time t1 is R1 and at a later time t2, it is R2. If the dacay constant of the material is λ, then

  • R1 = R2 e-λ(t1 -t2 )

  • R1 = R2 eλ(t1 -t2 )

  • R1 = R2 e(t2 /t1 )

  • R1 = R2

Solution

A.

R1 = R2 e-λ(t1 -t2 )

The decay rate R of radioactive materials the number of decays per second.
From radioactive decay law.
      negative dN over dt proportional to space straight N space space or space space space minus dN over dt space equals λN
Thus,   straight R equals negative dN over dt space space or space space straight R space proportional to space space straight N
or         straight R space equals space λN space space space or space space space straight R space equals space λN subscript 0 straight e to the power of negative λt end exponent                    ...(i)
where straight R subscript 0 space equals space λN subscript 0 is the activity of the radioactive material at time t = 0.
At time t1,  straight R subscript 1 space equals space straight R subscript 0 straight e to the power of negative λt subscript 1 end exponent       ...(ii)
At time t2,   straight R subscript 2 space equals space straight R subscript 0 straight e to the power of negative λt subscript 2 end exponent      ...(iii)
Dividing Eq. (ii) by (iii), we have,
                      straight R subscript 1 over straight R subscript 2 space equals space straight e to the power of negative λt subscript 1 end exponent over straight e to the power of negative λt subscript 2 end exponent space equals space straight e to the power of negative straight lambda left parenthesis straight t subscript 1 minus straight t subscript 2 right parenthesis end exponent
or space space space straight R subscript 1 space equals space straight R subscript 2 straight e to the power of negative straight lambda left parenthesis straight t subscript 1 minus straight t subscript 2 right parenthesis end exponent

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