-->

Wave Optics

Question
CBSEENPH12040088

The binding energy of deuteron is 2.2 MeV and that of  He presubscript 2 presuperscript 4 is 28 MeV. If two deuterons are fused to form one He presubscript 2 presuperscript 4 then the energy released is

  • 25.8 MeV

  • 23.6 MeV

  • 19.2 MeV

  • 30.2 MeV

Solution

B.

23.6 MeV

The reaction can be written as:
straight H presubscript 1 superscript 2 space plus space straight H presubscript 1 superscript 2 space space space rightwards arrow space space space He presubscript 2 superscript 4 space plus space energy
The energy released in the reaction is difference of binding energies of daughter and parent nuclei.
Hence, energy released.
 = binding energy of He presubscript 2 superscript 4 - 2 x binding energy of straight H presubscript 1 superscript 2
 = 28 - 2 x 2.2 = 23.6 MeV

Some More Questions From Wave Optics Chapter