Question
Monochromatic light of frequency 6.0 x 1014 Hz is produced by a laser. The power emitted is 2 x 10-3 W The number of photons emitted, on the average, by the source per second is:
-
5 x 1015
-
5 x 106
-
5 x 1017
-
5 x 1014
Solution
A.
5 x 1015
Photons are the packest of energy.
Power emitted,
P = 2 x 10-3 W
Energy of photon,
E = hv
= 6.6 x 10-34 x 6 x 1014 J
h being Planck's constant
Number of photons emitted per second
n = P/E
=
= 5 x 1015