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Wave Optics

Question
CBSEENPH12040082

Monochromatic light of frequency 6.0 x 1014 Hz is produced by a laser. The power emitted is 2 x 10-3 W The number of photons emitted, on the average, by the source per second is:

  • 5 x 1015

  • 5 x 106

  • 5 x 1017

  • 5 x 1014

Solution

A.

5 x 1015

Photons are the packest of energy.
Power emitted,
P = 2 x 10-3 W
Energy of photon,
E = hv
= 6.6 x 10-34 x 6 x 1014 J
h being Planck's constant
Number of photons emitted per second
n = P/E
 =fraction numerator 2 space straight x space 10 to the power of negative 3 end exponent over denominator 6.6 space straight x space 10 to the power of negative 34 end exponent space straight x space 6 space straight x space 10 to the power of 14 end fraction
 = 5 x 1015

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