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Electrostatic Potential And Capacitance

Question
CBSEENPH12040081

In mass spectrometer used for measuring the masses of ions, the are initially accelerated by an electric potential V and then made to describe semicircular paths of radius R using a magnetic field B. If V and B are kept constant, the ratio open parentheses fraction numerator charge space on space the space ion over denominator mass space of space the space ion end fraction close parentheses will be proportional to:

  • 1/R

  • 1/R2

  • R2

  • R

Solution

B.

1/R2

Centripetal force os provided by the magentic force qvB.
The radius of the orbit in which ions moving is determined by the relation as given below.
mv squared over straight R space equals space qvB
where m is the mass, v is velocity, q is charge of ion and B is the flux density of the magnetic field, so that qvB is the magnetic force acting on the ion, and mv2/R is the centripetal force on the ion moving in a curved path of radius R. The angular frequency of rotation of the ions about the vertical field B is given by

straight omega space equals straight v over straight R space equals space qB over straight m space equals space 2 πv
where space straight v space is space frequency.
Energy space of space ion space is space given space by
straight E space equals space 1 half mv squared space equals 1 half straight m space left parenthesis Rω right parenthesis squared
equals 1 half mR squared straight B squared space straight q squared over straight m squared
or space straight E thin space equals space 1 half fraction numerator straight R squared straight B squared straight q squared over denominator straight m end fraction space space... space left parenthesis straight i right parenthesis space
If ions are accelerated by electric potential V, then energy attained by ions
 E =qV ..... (ii)
From Eqs. (i) and (ii), we get
qV space space equals space 1 half fraction numerator straight R squared straight B squared straight q squared over denominator straight m end fraction
or space straight q over straight m space equals fraction numerator 2 straight V over denominator straight R squared straight B squared end fraction
If V and B are kept constant, then
straight q over straight m space proportional to space 1 over R squared

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