Question
The primary and secondary coil of a transformer have 50 and 1500 turns respectively. If the magnetic flux Φ linked with the primary coil is given Φ = Φo +4t, where Φ is in weber, t is time is second and Φo is a constant the output voltage across the secondary coil is:
-
90 V
-
120 V
-
220 V
-
30 V
Solution
B.
120 V
The magentic flux linked with the primary coil is given by
Φ = Φo +4t
So, voltage across primary
Vp = dΦ/dt = d(Φ+dt) /dt
= 4 volt (Φ = constant)
Also, we have
Np = 50 and Ns = 1500
From relation ,
Vs/Vp = Ns/Np
Vs = 4 x (1500/50)
= 120 V
