Question
Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300 m/s. What is the phase difference between the oscillation of two points?
-
π/3
-
2π/3
-
π
-
π/6
Solution
B.
2π/3
Phase difference = (2π/λ) x path difference
path difference between two points,
Δ x = 15-10 = 5 m
Time period, T = 0.05 s
⇒ frequency v = 1/T
= 1/0.05 = 20 Hz
Velocity, v= 300 m/s
therefore, wavelength, λ = v/V = 300/20 = 15 m
Hence, phase difference
Δ Φ = (2π /λ) x Δ x
= (2π /15) x 5 = (2π /3)
