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Electric Charges And Fields

Question
CBSEENPH12040061

A circular disc of radius 0.2 m is placed in a uniform magnetic field of induction in1 over straight pi open parentheses Wb over straight m squared close parentheses such a way that its axis makes an angle of 60o with.bold B with bold rightwards arrow on top The magnetic flux linked with the disc is 

  • 0.02 Wb

  • 0.06 Wb

  • 0.05 Wb

  • 0.01 Wb

Solution

A.

0.02 Wb

The magnetic flux  Φ passing through a plane surface of area A placed in a uniform magnetic field B is given by 
Φ = BA Cos θ
where θ is the angle between the direction of B and the normal to the plane.
Here,
straight theta space equals 60 to the power of straight o space comma space straight B space equals space 1 over straight pi space Wb divided by straight m squared comma space straight A space equals space straight pi space left parenthesis 0.2 right parenthesis squared
therefore comma space straight ϕ space equals space 1 over straight pi space straight x space straight pi space left parenthesis 0.2 right parenthesis squared space straight x space cos space 60
space equals space left parenthesis 0.2 right parenthesis squared space straight x space 1 half
space equals space 0.02 space Wb