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Electrostatic Potential And Capacitance

Question
CBSEENPH12040060

In the circuit shown, the current through the 4 Ω resistor is 1 A when the points P and M are connected to a DC voltage source. The potential difference between the point M and N is 




  • 1.5 V

  • 1.0 V

  • 0.5 V

  • 3.2 V

Solution

D.

3.2 V

In parallel resistances, the potential difference across them is same.
Potential difference across PM
V = 4 x 1 = 4 Volt (ie, across 4 Ω)
Equivalent resistance of lower side arm, 
straight R subscript eq space equals space 1 space plus fraction numerator 0.5 space straight x space 0.5 over denominator 0.5 space plus 0.5 end fraction space equals space 1.25 space straight capital omega
Now the circuit can be shown as

Let current I flow in lower branch, so 
1.25 I = 4V
I = 4/1.25 = 3.2 A
Therefore, 3.2 A current flows in 1 Ω resistance, hence potential difference between M and N is
V' = 3.2 x 1 = 3.2 volt

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