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Wave Optics

Question
CBSEENPH12040052

A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of 3 x 106 ms-1. The velocity of the particle is.

(mass of electron = 9.1 x 10-31 kg)

  • 2.7 x 10-18 ms-1

  •  9 x 10-2 ms-1

  • 3 x 10-31 ms-1

  • 2.7 x 10-21 ms-1

Solution

A.

2.7 x 10-18 ms-1

wavelength of a particle is given by
straight lambda space equals space straight h over straight p
where space straight h space is space Planck apostrophe straight s space constant space and space wave space length space of space electron space is space given space by
straight lambda subscript straight e space equals space straight h over straight p subscript straight e
straight lambda space equals space straight lambda subscript straight e
straight p space equals straight p subscript straight e
mv space equals space straight m subscript straight e straight v subscript straight e
straight v equals space straight m subscript straight e straight v subscript straight e
Putting space the space under space given space data
straight m subscript straight e space equals space 9.1 space straight x space 10 to the power of negative 31 end exponent space kg comma space straight v subscript straight e space equals space 3 space straight x space 10 to the power of 6 space straight m divided by straight s end exponent
straight m space equals 1 space mg space equals space 1 space straight x space 10 to the power of negative 6 end exponent space kg
straight v equals space fraction numerator 9.1 space straight x space 10 to the power of negative 31 end exponent space straight x space 3 space straight x space 10 to the power of 6 over denominator 1 space straight x space 10 to the power of negative 6 end exponent end fraction
equals space 2 minus 7 space straight x space 10 to the power of negative 18 end exponent space ms to the power of negative 1 end exponent

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