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Electrostatic Potential And Capacitance

Question
CBSEENPH12040042

The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is

  • 1 half straight epsilon subscript straight o straight E squared divided by Ad
  • straight epsilon subscript straight o straight E squared divided by Ad
  • straight epsilon subscript straight o straight E squared Ad
  • 1 half straight epsilon subscript straight o straight E squared divided by Ad

Solution

C.

straight epsilon subscript straight o straight E squared Ad

Energy given be the cell
E =CV2
Here, C = capacitance of condenser = Aε subscript straight o over straight d

V = potential difference across the plate = Ed
therefore,
straight E equals space open parentheses Aε subscript straight o over straight d close parentheses space left parenthesis Ed right parenthesis squared
equals space Aε subscript straight o straight E squared straight d

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