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Work, Energy And Power

Question
CBSEENPH11026422
Wired Faculty App

If the linear momentum is increased by 50%, then kinetic energy will increase by

  • 0 %

  • 100 %

  • 125 %

  • 25 %

Solution

C.

125 %

Kinetic energy of a body

               K = p22m                                  K = 12 mv2

where p is the momentum of the body and m is the mass of the body

            p' = p + 50100p

            p' = 32 p

Assuming m remains constant

∴        K'K = p'p

           K'K= 94

% increase in kinetic energy

                      = K' - KK × 100%

                       = 94 - 1 × 100%

                       = 125 %

% increase in kinetic energy = 125 %

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