Question
If 10goficeis added to 40 g of water at 15°C, then the temperature of the mixture is(specific heat of water = 4.2 x 103 J kg-1K-1, Latent heat of fusion of ice = 3.36 x 105 J kg-1 )
15 oC
12 oC
10 oC
0 oC
Solution
D.
0 oC
Heat lost by water to come from 15 oC to 0 oC is
H1 = m s ΔT
H1 = × (4.2 × 103 ) × ( 15 0 )
H1 = 2520 J
Heat required to convert 10 g ice into 10 g water at 0°C is
H2 = mL
= × ( 3.36 × 105 )
H2 = 3360 J
Since H2 > H1, so the whole ice will not be converted into water, whereas the temperature of the whole water will be 0oC.
Therefore the temperature of the mixture is 0oC.
