A pendulum having a bob of mass m is hanging in a ship sailing along the equator form east to west. When the strip is stationary with respect to water, the tension in the string is T₀, The difference between T₀ and
earth attraction on the bob, is

$\frac{mg + m ω^{2} R}{2}$

$\frac{{mω}^{2} R}{3}$

$\frac{{mω}^{2} R}{2}$

mω² R

Solution

mω² R

The attraction of earth on the bob = Weight of bob = mg

Speed of ship due to rotation of the earth

Velocity = angular velocity × radius

v = ω R

Also due to the rotation of the earth, a centripetal force acts on the bob = mω² R on earth

The net force

T₀ = mg + mω² R

⇒ T₀ - mg = mω² R

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