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System Of Particles And Rotational Motion

Question
CBSEENPH11026321

A tangential force acting on the top of sphere of mass m kept on a rough horizontal place as shown in figure

                  

If the sphere rolls without slipping, then the acceleration with which the centre of sphere moves, is

  • 10 F7 m

  • F2 m

  • 3 F7 m

  • 7 F2 m

Solution

A.

10 F7 m

Let a be the acceleration of centre of sphere. The angular acceleration about the centre of the sphere is α = θr, as there is no slipping.

For the linear motion of the centre

   f + F = ma                  .....(i)

and for the rotational motion about the centre

  Fr - fr = I α

            = 25 mr2 ar

 ⇒  F - f = 25 ma           ....(ii)

From Eqs. (i) and (ii)

   2F = 75 ma

 ⇒  a  = 10 F7 m