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Motion In A Plane

Question
CBSEENPH11026319

The angle between two linear transmembrane domains is defined by following vectors a = i^ + j^ - k^ and  b = i^ - j^  +  k^

  • cos-1 13

  • cos-1 -13

  • sin-1 -13

  • sin-1 13

Solution

B.

cos-1 -13

The angle between two vectors is given by

       cosθ = a.bab

               = 1 - 1 - 13 × 3

⇒      cosθ = -13

⇒     θ = cos-1 -13