Question
A projectile is given an initial velocity of The cartesian equation of its path is ( Take g= 10 ms2 )
y = x 5x2
y = 2x 5x2
y = 2x 15 x2
y = 2x 25x2
Solution
B.
y = 2x 5x2
Given:-
The initial velocity of a projectile is given by
= ux + uy
Then,
ux = 1 = u cosθ
uy = 2 = u sinθ
∴
=
tanθ = 2
The equation of trajectory of a projectile motion is
y = x tanθ
= x tanθ
∴ y = (x × 2 )
y = 2x - 5x2