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Work, Energy And Power

Question
CBSEENPH11026387

A ball impinges directly on a similar ball at rest. The first ball is brought to rest by the impact. If half of the kinetic energy is lost by impact, the value of coefficient of restitution is

  • 122

  • 13

  • 12

  • 32

Solution

C.

12

Let u1 and v1 be the initial and final velocities of ball 1 and u2 and v2 be the similar
quantities for ball 2.

Here, u2 = 0 and v1 = 0

∴    initial K.E 

          Ki =  12 mu12 + 12 mu22

          Ki12 mv12

and  final K.E

          Kf12 mv12 + 12 mv22

          Kf12 mv22

Loss of KE

         ΔK = Ki - Kf

              = 12 m12 - 12 mv22

According to question

        12 12 mv12 = 12 mu12 - 12 mu22

( since half KE is lost by impact )

        u12 = 2 v22

 ⇒     v2 = u12

The coefficient of restitution is defined as the ratio of the final velocity to the initial velocity after their collision.

∴  Coefficient of restitution,

    e = v2 - v1u1 - u2 

        = v2v1

   e = 12