Question
What is the radius of curvature of the parabola traced out by the projectile in the previous problem at a point where the particle velocity makes an angle with the horizontal?
Solution
A.
Let v be the velocity at the point where it makes an angle with the horizontal.
The horizontal component remains unchanged. So
vm = u cosθ
⇒ v = .....(i)
From figure
mg cos
r =
Putting the value of v from Eq (i), we get
r =