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Motion In A Plane

Question
CBSEENPH11026208

A projectile is thrown in the upward direction making an angle of 60° with the horizontal direction with a velocity of 147 ms-1 Then the time after which its inclination with the horizontal is 45°, is

  • 15 s

  • 10.98 s

  • 5.49 s

  • 2.745 s

Solution

C.

5.49 s

At the two points of the trajectory during projection, the horizontal component of the velocity is the same. 

The horizontal component of velocity at angle 60o  =  Horizontal component of velocity at 45o

  ⇒           u cos 60o = v sin 45o

                147 × 12 = ν × 12           v   = 1472 m/s 

Vertical component of u = u sin 60o

                             = 147 32 m

Vertical component of v = v sin 45o

                         147 2 × 12 = 1472m

but             vy = uyα t

                  1472 = 14732 - 9.8 t                  9.8t  = 1472 3 - 1

                    t = 5.49 s