A projectile is thrown in the upward direction making an angle of 60° with the horizontal direction with a velocity of 147 ms-1 Then the time after which its inclination with the horizontal is 45°, is
15 s
10.98 s
5.49 s
2.745 s
C.
5.49 s
At the two points of the trajectory during projection, the horizontal component of the velocity is the same.
The horizontal component of velocity at angle 60o = Horizontal component of velocity at 45o
⇒ u cos 60o = v sin 45o
Vertical component of u = u sin 60o
Vertical component of v = v sin 45o
but vy = uy +
t = 5.49 s