Question
Two boys are standing at the ends A and B of a ground, where AB= a. The boy at B starts running in a direction perpendicular to AB with velocity The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is
Solution
B.
Distance covered by boy A in time t
AC = vt ...(i)
Distance covered by boy B in time t
BC = v1 t ... (ii)
Using Pythagourus theorem
AC2 = AB2 + BC2
( vt )2 = a2 + (v1 t)2
⇒
⇒
⇒
