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Work, Energy And Power

Question
CBSEENPH11026285

A gas expands 0.25 m3 at constant pressure 103 N/m2, the work done is

  • 250 N

  • 250 W

  • 250 J

  • 2.5 erg

Solution

C.

250 J

From the formula of work done

       W = P ΔV

Where W is the work done, P is the pressure and ΔV is the change in volume

    W = 103 × 0.25

     W = 250 J