Question
A car of mass 1000 kg moves on a circular track of radius 40 m. If the coefficient of friction is 1.28. The maximum velocity with which the car can be moved, is
22.4 m/s
112 m/s
m/s
1000 m/s
Solution
A.
22.4 m/s
A car moves in a circular track so it perform circular motion.
According to second law the force providing this acceleration is
fc =
But according to static friction
fs ≤ μs N
f =
Given:- μ = 1.28
where μ is the coefficient of friction
R = 40 m
The maximum velocity
vmax =
=
vmax = 22.4 m/s