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Laws Of Motion

Question
CBSEENPH11026281

A car of mass 1000 kg moves on a circular track of radius 40 m. If the coefficient of friction is 1.28. The maximum velocity with which the car can be moved, is

  • 22.4 m/s

  • 112 m/s

  • 0.64 × 401000 × 100m/s

  • 1000 m/s

Solution

A.

22.4 m/s

A car moves in a circular track so it perform circular motion. 

According to second law the force providing this acceleration is

           fcmv2R

But according to static friction

         fs ≤ μs N

     f = m v2R  μs N

     vmax = μ R g

Given:-  μ = 1.28 

where μ is  the coefficient of friction 

  R = 40 m 

The maximum velocity

          vmaxμ R g 

                   = 1.28 × 40 × 9.8

             vmax = 22.4 m/s