Question
A coin is dropped in a lift. It takes time t1 to reach the floor when lift is stationary. It takes time t2 when lift is moving up with constant acceleration. Then,
t1 ≥ t2
t2 > t1
t1 = t2
t1 >> t2
Solution
A.
t1 ≥ t2
An object that is in flight after being thrown or projected is called projectile.
For stationary lift t1 =
and when the lift is moving up with constant acceleration of coin is more than g hence will take less time.
t2 =
∴ t1 > t1