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Mechanical Properties Of Fluids

Question
CBSEENPH11026250

The cylindrical tube of a spray pump has a cross-section of 8 cm2 , one end of which has 40 fine holes each of area 10-8 m2. If the liquid flows inside the tube with a speed of 0.15 m min-1 the speed with which the liquid is ejected through the holes is

  • 50 m/s

  • 5 m/s

  • 0.05 m/s

  • 0.5 m/s

Solution

B.

5 m/s

One of the fundamental principles used in the analysis of uniform flow is known as continuity of flow. This principle is derived from the fact that mass is always conserved in fluid systems regardless of the pipeline complexity or direction of flow.

According to the equation of continuity,

          Q = A1 V1 = A2 V2

                  a v = constant                       ... (i)

Where Q is the volumetric flow rate

         A is the cross-sectional area of flow

          V is the mean velocity

Area of cross secrction of the spray pump,

a1 = 8 cm2 = 8 × 10-4 m2

number of holes n = 40

          v1 = 0.15 m min-10.1560

         ∴   For tube, 

            8 × 10-4 × 0.1560 = a1 v1

    For holes,

             40 × 10-8 × v   = a2 v2 

According to law of continuity from equation (i)

∴                a2 v = a1 v1

∴         40 × 10-8 × v  = 8 × 10-4 × 0.1560

⇒                   v = 8 × 10-4 × 0.1540 × 10-8 × 60

⇒                    v = 5 m/s