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Waves

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A closed organ pipe of length 20 cm is sounded with tuning fork in resonance. What is frequency of tuning fork? (v = 332 m/s)

300 Hz

350 Hz

375 Hz

415 Hz

Solution

415 Hz

If we adjust the length of air-column in closed organ pipe as such its any natural frequency equals to the frequency of tuning fork, then the amplitude of forced vibrations of air-column increases very much. This is the state of resonance.

At first resonance

$l = \frac{λ}{4}$

So, frequency of tuning fork

f = $\frac{v}{λ}$

f = $\frac{v}{4 l}$

Given, l = 20 cm = 0.2 m

v = 332 m/s

Hence

$f = \frac{0.332}{4 \times 0.2}$

f = 415 Hz

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Waves

A closed organ pipe of length 20 cm is sounded with tuning fork in resonance. What is frequency of tuning fork? (v = 332 m/s)

300 Hz

350 Hz

375 Hz

415 Hz

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For Daily Free Study Material Join wiredfaculty

Waves

A closed organ pipe of length 20 cm is sounded with tuning fork in resonance. What is frequency of tuning fork? (v = 332 m/s) 300 Hz 350 Hz 375 Hz 415 Hz

Some More Questions From Waves Chapter

The sound waves after being converted into electrical waves are not transmitted as such because

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A closed organ pipe of length 20 cm is sounded with tuning fork in resonance. What is frequency of tuning fork? (v = 332 m/s)

300 Hz

350 Hz

375 Hz

415 Hz